Easy
A system of equations is given.
y+2=3(x−1)y+2=3(x-1)y+2=3(x−1)
y=−2x+10y=-2x+10y=−2x+10
What is the solution to the system?
(x=3,y=4)(x=3, y=4)(x=3,y=4)
(x=2,y=6)(x=2, y=6) (x=2,y=6)
(x=1,y=0)(x=1, y=0) (x=1,y=0)
(x=−1,y=−2)(x=-1, y=-2)(x=−1,y=−2)
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