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Question

Difficulty Level:

Easy

MCQ

Aoi tried to reduce the following expression to lowest terms:

$\frac{3 x+3}{x^{2}-1}$

This is her work:

Factoring the numerator: $3 {x}+3=3({x}+1)$

Factoring the denominator: $x^{2}-1=({x}+1)({x}-1)$

Finding excluded values: : $x \neq 0$ and $x \neq \pm 3$

Reducing to lowest terms:

$\frac{3 x+3}{x^{2}-1}=\frac{3(x+1)}{(x+1)(x-1)}=\frac{3}{x+1}$

What mistake did Aoi make?

Select all that apply :

She excluded $x=0$ , which doesnot make the denominator equal to 0 .

She excluded $x=1$ , which doesnot make the numerator equal to zero.

She excluded $x=-1$ whick doesnot make, the new expression equal to 20 .

She did not factor the denominator correctly.

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