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Dian received the following problem:

A particle moves in a straight line with velocity ${v}({t})$ meters per second (graphed), where $t$ is time in seconds. At ${t}=2$ , the particle’s distance from the starting point was 10 meters in the positive direction. What is the particle’s position at ${t}=9$ seconds? Which expression should Dian use to solve the problem?

$10+\int_{2}^{9} v(t) d t$

$10+\int_{0}^{9} v(t) d t$

$\int_{0}^{9} v(t) d t$

$\int_2^9 v(t) d t$

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