Medium
Events AAA and BBB are independent with P(AP(AP(A and B)=0.25B)=0.25B)=0.25
Enter possible probabilities for events AAA and BBB.
P(A)=P(B)=0.5P(A)=P(B)=0.5P(A)=P(B)=0.5
P(A)=0.05,P(B)=0.5P(A)=0.05, P(B)=0.5P(A)=0.05,P(B)=0.5
P(A)=0.15,P(B)=0.25P(A)=0.15, P(B)=0.25P(A)=0.15,P(B)=0.25
P(A)=0.5,P(B)=0.15P(A)=0.5, P(B)=0.15P(A)=0.5,P(B)=0.15
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