Medium
Find all the solutions of the equations x+4x−1=−x2+3x+12(x+3)(x−1)\frac{x+4}{x-1}=\frac{-x^{2}+3 x+12}{(x+3)(x-1)}x−1x+4=(x+3)(x−1)−x2+3x+12
0,−20,-2 0,−2
0,1,−20,1,-2 0,1,−2
0,3,50,3,5 0,3,5
−1,2,3-1,2,3−1,2,3
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