Find BC. Round to nearest tenth ![](http://admin.getprephub.com/media/editor/t19_20220823205359222822.png)

In the given figure, $$b=13, c=6, m \angle A=91^{\circ}$$ By cosine law, $$a^{2}=b^{2}+c^{2}-2 b c \cos (m\langle A) $$ or,$$a^{2}=13^{2}+6^{2}-2.13 .6(\cos 9 i^{\circ}) $$ or,$$a \approx 14.4$$

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MCQ

Find BC. Round to nearest tenth

Select all that apply :

$14.4$

$12.8$

$16.3$

$19.5$

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