Find $$\sin (2 \cdot \angle A B C)$$. ![](http://admin.getprephub.com/media/editor/tei16_20230123200759501263.png)

Here, $$ \text { Let, }< A B C=\theta $$ $$ \sin \theta=\frac{A C}{A B}=\frac{\text{Opposite leg length}}{\text{Hypotenuse}}=\frac{8}{10}=\frac{4}{5}$$ $$\cos \theta=\frac{\text{Adjacent leg length}}{\text{Hypotenuse}}=\frac{B C}{A B}=\frac{6}{10}=\frac{3}{5} $$ $$ \sin \theta=\sin (2<A B C)=\sin 2\theta=2 \sin \theta \cos \theta=2 \cdot \frac{4}{5} \cdot \frac{3}{5}=\frac{24}{25} $$

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Question

Difficulty Level:

Medium

MCQ

Find $\sin (2 \cdot \angle A B C)$ .

Select all that apply :

$\frac{24}{25}$

$\frac{25}{24}$

$\frac{12}{13}$

$\frac{13}{12}$

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