Find the $$3^{\text {rd }}$$ term in the sequence. ![](http://admin.getprephub.com/media/editor/seq11_20221124205613837801.png)

Given that, $$b(1)=-2, b(n)=b(n-1)-7$$ Putting $$n=3$$, $$b(3) =b(2)-7 $$ $$=b(1)-7-7 $$ $$=b(1)-14 $$ $$=-2-14 $$ $$=-16 $$

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Question

Difficulty Level:

Easy

MCQ

Find the $3^{\text {rd }}$ term in the sequence.

Select all that apply :

$-16$

$14$

$-14$

$16$

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