Easy
Find the zeros of the polynomial p(x)=(2x2+7x+5)(x−3)p(x)=(2 x^{2}+7 x+5)(x-3)p(x)=(2x2+7x+5)(x−3)
−1,−52,3-1,-\frac{5}{2}, 3 −1,−25,3
1,52−31, \frac{5}{2} -3 1,25−3
0,1,20,1,20,1,2
3,−3,−13,-3,-13,−3,−1
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