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Question
Difficulty Level:

Easy

MCQ

Given here:

g(x)=3x2g(x)=\frac{3}{x-2}

and h(x)=9x{h}({x})=9 x

Danielle tried to evaluate (gh)(7)(g \circ h)(7) but she made a mistake. Here is her work.

Step 1

g(7)=372=35g(7)=\frac{3}{7-2}=\frac{3}{5}

Step 2

h(7)=9(7)=63h(7)=9(7)=63

Step 3

(gh)(7)=35.63=1895(g \circ h)(7)=\frac{3}{5} .63=\frac{189}{5}

What is the mistake in Danielle’s work?

Select all that apply :

(gh)(7)=g(h(7))notg(7)h(7)(g \circ h)(7)=g(h(7)) not g(7) \cdot h(7)

(gh)(7)=h(g(7)) not g(7)h(7)(g \circ h)(7)=h(g(7)) \text { not } g(7) \cdot h(7)

 g(7)=13not35{~g}(7)=\frac{1}{3} {not} \frac{3}{5}

 h(7)=35,not13{~h}(7)=\frac{3}{5}, not \frac{1}{3}

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