Prephub

Question

Difficulty Level:

Easy

MCQ

Given here:

$g(x)=\frac{3}{x-2}$

and ${h}({x})=9 x$

Danielle tried to evaluate $(g \circ h)(7)$ but she made a mistake. Here is her work.

Step 1

$g(7)=\frac{3}{7-2}=\frac{3}{5}$

Step 2

$h(7)=9(7)=63$

Step 3

$(g \circ h)(7)=\frac{3}{5} .63=\frac{189}{5}$

What is the mistake in Danielle’s work?

Select all that apply :

$(g \circ h)(7)=g(h(7)) not g(7) \cdot h(7)$

$(g \circ h)(7)=h(g(7)) \text { not } g(7) \cdot h(7)$

${~g}(7)=\frac{1}{3} {not} \frac{3}{5}$

${~h}(7)=\frac{3}{5}, not \frac{1}{3}$

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