In quadrilateral $$A B C D, \overline{A B} \cong \overline{C D}$$ and $$\overline{B C} \cong \overline{A D}$$, as shown. ![](http://admin.getprephub.com/media/editor/Screenshot%202023-08-08%20at%206.23.02%20PM_20230808162324202514.png) Select the correct statement to complete the proof showing that $$\triangle A B C \cong \triangle C D A$$

In $$\triangle A B C$$ and $$\triangle C D A$$, (i) $$\overline{B C} \cong \overline{A D}$$ [given] (ii) $$\overline{A B} \cong \overline{C D}$$ [given] (iii) $$\overline{A C} \cong \overline{C A}[$$ common] Therefore, by SAS rule of congruency, $$\triangle A B C \cong \triangle C D A$$

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In quadrilateral $A B C D, \overline{A B} \cong \overline{C D}$ and $\overline{B C} \cong \overline{A D}$ , as shown.

Select the correct statement to complete the proof showing that $\triangle A B C \cong \triangle C D A$

Select all that apply :

$\overline{A C} \cong \overline{C A}$

$\overline{A B} \cong \overline{A D}$

$\angle A B C \cong \angle C D A$

$\angle B A C \cong \angle A C D$

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