Medium
Rewrite the expression (b2)37(b^{2})^{\frac{3}{7}}(b2)73 in the form bnb^{n}bn
b67b^{\frac{6}{7}}b76
b47b^{\frac{4}{7}}b74
b57b^{\frac{5}{7}}b75
b27b^{27}b27
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