Right triangle FHG is shown. ![](http://admin.getprephub.com/media/editor/d15_20230225224902825213.png) The sine of $$<{F}$$ is $$0.53$$. What is the cosine of $$<{H}$$ ? Round your answer to the nearest hundredth as needed.

Given that, $$\sin F=0.53$$ In the right triangle $$\triangle {F} {G H}$$, $${m}<{F}+{m}<{G}+{m}<{H}={1 8 0}^{\circ}$$ Or, $$m<F+90^{\circ}+m<H=180^{\circ}$$ Or, $${m}<{F}+{m}<{H}=90^{\circ}$$ Or, , $${m}<{H}=90-{m}<{F} \ldots \ldots \ldots \ldots \ldots \ldots \ldots(i)]$$ Therefore $$<{F}$$ and $$<{H}$$ are complementary to each other. $$\sin F=\cos (90-F)=\cos H$$ [from (i)] therefore, $$\cos H=\sin F=0.53$$

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Right triangle FHG is shown.

The sine of $<{F}$ is $0.53$ .

What is the cosine of $<{H}$ ? Round your answer to the nearest hundredth as needed.

Select all that apply :

0.53

0.93

0.78

0.63

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