Easy
Solve the equation dydx=5y2cos(x)\frac{d y}{d x}=5 y^{2} \cos (x)dxdy=5y2cos(x)
y=−15sin(x)+cy=-\frac{1}{5 \sin (x)}+cy=−5sin(x)1+c
y=1−5cos(x)+cy=\frac{1}{-5 \cos (x)}+cy=−5cos(x)1+c
y=−5sin(x)+cy=-\frac{5}{\sin (x)+c}y=−sin(x)+c5
y=−5cos(x)+cy=-\frac{5}{\cos (x)+c}y=−cos(x)+c5
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