Medium
Solve the following equation 3z+1=z2+6z+33 z+1=\sqrt{z^{2}+6 z+3}3z+1=√z2+6z+3 for zzz.
12\frac{1}{2}21
13\frac{1}{3}31
14\frac{1}{4}41
−12 \frac{-1}{2}2−1
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