The coordinates of the vertices of triangle $$X Y Z$$ are $$X(-2,-1)$$, $$Y(6,8)$$ and $$Z(8,4)$$. Triangle $$X Y Z$$ is dilated by a scale factor of $$\frac{3}{2}$$ with the origin as the center of dilation to create triangle $$X^{\prime} Y^{\prime} Z^{\prime}$$. ![](http://admin.getprephub.com/media/editor/Screenshot%202023-06-12%20at%201.30.51%20PM_20230612113108830988.png) If $$(x, y)$$ represents the location of any point on triangle $$X Y Z$$, which ordered pair represents the location of the corresponding point on triangle $$X^{\prime} Y^{\prime} Z^{\prime}$$ ?

Given that, Triangle $$X Y Z$$ is dilated by a scale factor of $$\frac{3}{2}$$ with the origin as the center of dilation to create triangle $$X^{\prime} Y^{\prime} Z^{\prime}$$. Therefore, new co-ordinate = $$\frac{3}{2}\times $$ original co-ordinate . Hence, The correct option is A $$(\frac{3}{2} x, \frac{3}{2} y)$$

Prephub

The coordinates of the vertices of triangle $X Y Z$ are $X(-2,-1)$ , $Y(6,8)$ and $Z(8,4)$ . Triangle $X Y Z$ is dilated by a scale factor of $\frac{3}{2}$ with the origin as the center of dilation to create triangle $X^{\prime} Y^{\prime} Z^{\prime}$ .

If $(x, y)$ represents the location of any point on triangle $X Y Z$ , which ordered pair represents the location of the corresponding point on triangle $X^{\prime} Y^{\prime} Z^{\prime}$ ?

A $(\frac{3}{2} x, \frac{3}{2} y)$

B $(x+\frac{3}{2}, y+\frac{3}{2})$

C $(\frac{2}{3} x, \frac{2}{3} y)$

D $(x+\frac{2}{3}, y+\frac{2}{3})$

－ Create Free Account

Create a free account to view solution to this Question

－ Create Free Account

Create a free account to view solution to this Question