$$\triangle A B C$$ is translated 6 units to the left and 1 unit up to create $$\triangle A^{\prime} B^{\prime} C^{\prime}$$. ![](http://admin.getprephub.com/media/editor/tp3_20230125193147737909.png) What is the area of $$\triangle A B C$$ ?

Since $$\triangle A B C$$ is translated 6 units to the left and 1 unit up to create $$\triangle A^{\prime} B^{\prime} C^{\prime}$$. Comparing $$\triangle A B C$$ and $$\triangle A^{\prime} B^{\prime} C^{\prime}$$, $$A B=A^{\prime} B^{\prime}=6.1$$ units (height),$$B C($$ Base $$)=2$$ unit Therefore the area of $$\triangle A B C=\frac{1}{2} \times 6.1 \times 2=6.1$$ unit $$^{2}$$

Prephub

Free Sample Paper! Boost your grades with additional practice papers.

Question

Difficulty Level:

Easy

MCQ

$\triangle A B C$ is translated 6 units to the left and 1 unit up to create $\triangle A^{\prime} B^{\prime} C^{\prime}$ .

What is the area of $\triangle A B C$ ?

Select all that apply :

$6.1$

$2.3$

$5.6$

$4.5$

31 Claps

－ Create Free Account

Create a free account to view solution to this Question

By signing up, you accept PrepHub’sterms of serviceand dataprivacy policy.

－ Create Free Account

Create a free account to view solution to this Question

By signing up, you accept PrepHub’sterms of serviceand dataprivacy policy.