Triangle $${JKL}$$ is shown. ![](http://admin.getprephub.com/media/editor/p21_20230225214709443640.png) Triangle $$DEF$$ is congruent to triangle $$JKL$$. Which triangle could be DEF?

Two triangles are said to be congruent if the sides and the angles of two triangles are equal. Given that, $$\triangle D E F \cong \triangle J K L$$ $${m}<{D}={m}<{J}, {m}<{E}={m}<{K}, {m}<{F}={m}<{L}$$ given that, $${m}<{K}=40$$, therefore, $${m}<{E}=40$$ $$\overline{D E}=\overline{J K}, \overline{E F}=\overline{K L}, \overline{D F}=\overline{J L} \quad[$$ From $$\triangle D E F \cong \Delta J K L$$ ] Given that, $$\overline{K L}=12, \overline{J K}=16.9$$ Therefore, $$\overline{E F}=\overline{K L}=12, \overline{D E}=\overline{J K}=16.9$$ Out of the four options, only the triangle mentioned below satisfies the constraints . ![](http://admin.getprephub.com/media/editor/p21sssss_20230225214736500047.png) Hence, this is the possible DEF.