Medium
What is the inverse of the function g(x)=−x−2x+4{g}({x})=\frac{-x-2}{x+4}g(x)=x+4−x−2 ?
4x+2−1−x\frac{4 x+2}{-1-x}−1−x4x+2
2+2x1+x\frac{2+2 x}{1+x}1+x2+2x
−x−2x+4\frac{-x-2}{x+4}x+4−x−2
x+2x−4\frac{x+2}{x-4}x−4x+2
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