Medium
What is the inverse of the function h(x)=3−xx+1h(x)=\frac{3-x}{x+1}h(x)=x+13−x ?
3−xx+1\frac{3-x}{x+1}x+13−x
3−xx−1\frac{3-x}{x-1}x−13−x
x+3x+1\frac{x+3}{x+1}x+1x+3
−x−3x−1\frac{-x-3}{x-1}x−1−x−3
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