Prephub

Zaiden received the following problem:

A particle moves in a straight line with velocity $v(t)$ meters per second (graphed), where $t$ is time in seconds. At $t=6$ , the particle’s distance from the starting point was 5 meters in the positive direction. What is the particle’s displacement between $t=6$ and $t=9$ seconds?

Which expression should Zaiden use to solve the problem?

$\int_{6}^{9} v(t) d t$

$5+\int_{6}^{9} v(t) d t$

$v(9)-v(6)$

$v(9)$

－ Create Free Account

Create a free account to view solution to this Question

－ Create Free Account

Create a free account to view solution to this Question