Quiz about Equations

Question 1

The equation shown is used to find the force of gravity, F, between two objects, where $$G$$ is the gravitational constant, $$m_1$$ and $$m_2$$ are the masses of the two objects, and $$r$$ is the distance between the two objects.

$${F}=\frac{G m_1 m_2}{r^{2}}$$

Which equation correctly shows the distance between the two objects?

Accepted Answer

Covalent bond

Answer

$${r}=\sqrt{\frac{G m_1 m_2}{F}}$$

Answer

$${r}=\sqrt{\frac{F}{G m_1 m_2}}$$

Answer

$$ {r}=\frac{\sqrt{G m_1 m_2}}{F} $$

Answer

$${r}=\frac{\sqrt{F}}{G m_1 m_2}$$

Question 2

Solve for $$r, \frac{4 r}{5 r+6}=\frac{1}{6}$$

Accepted Answer

Covalent bond

Answer

$$\frac{6}{31}$$

Answer

$$ \frac{6}{19}$$

Answer

$$\frac{31}{6}$$

Answer

$$ \frac{19}{4}$$

Question 3

Solve for $$t$$, if $$ \frac{t+9}{t+4}=5$$

Accepted Answer

Covalent bond

Answer

$$-\frac{11}{4}$$

Answer

$$ \frac{11}{4}$$

Answer

$$ \frac{11}{2}$$

Answer

$$-\frac{11}{8}$$

Question 4

Solve for $$q$$ , if $$\frac{2}{2 q+3}=\frac{1}{8}$$

Accepted Answer

Covalent bond

Answer

$$\frac{13}{2}$$

Answer

$$-\frac{13}{2}$$

Answer

$$ \frac{2 }{19}$$

Answer

$$\frac{4}{13}$$

Question 5

An equation is given.

$${A}=4 \pi r^{2}$$

Solve the equation for $$r$$.

Accepted Answer

Covalent bond

Answer

$$r=\sqrt{\frac{A}{4 \pi}}$$

Answer

$$r=\sqrt{\frac{A}{23 \pi}}$$

Answer

$$r=\frac{A}{4}$$

Answer

$$r=\sqrt{\frac{1}{4 \pi}}$$

Equations Algebra 2 Maths Problems and Solutions

Many students find Equations for Algebra 2 particularly challenging. Strengthen your concepts and gain confidence for your exams by solving free questions for Equations from for Algebra 2 preparation.